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#Implement 3 stacks in a single array how to
#Implement 3 stacks in a single array full

With this article at OpenGenus, you must have the complete idea of how to design and implement K stacks in one array. if index in top is greater than first index then we will return value in arr at index top, store -1 in place of arr and decrease side of stack by 1ĬoutThe last element is the top of the stack. if top=(stack_no*n)/k and arr]!=-1 means top of stack is first index of stack and there is some value present in starting index of current stack therefore we will return value at top of stack and store -1 in arr at starting index of current stack Example 1: Input: target 1,3, n 3 Output: 'Push','Push','Pop','Push' Explanation: Initially the stack s is empty.What Is A Stack A stack is a data structure that is based on the concept of last-in-first-out. if top (stack_no*n)/k and arr]-1 means top of stack is equal to first index of stack and value in same index at arr is -1, hence stack is empty so we will just print stack is empty as there is no element present in stack The exercise is: Describe how you could use a single array to implement three stacks.

#Implement 3 stacks in a single array full

If top+1=((stack_no+1)*n)/k then we will print stack is full as ((stack_no+1)*n)/k is first element of stack who is next to current stack If top (stack_no*n)/k and arr]-1 then stack is empty so we can add insert element in stack

for removing element from stack first we will check if stack is empty or not if yes then we will simply print stack is empty.

for removing values from stack we will use pop function.

if not then add value at top of the stack A simple method for implementing kstacks is to divide the array into k slots of size no/k each and assign the slots to various stacks, i.e., use arr10 to arr1.

for inserting element in stack first we will check if stack is full or not if yes then we will simply print stack is full.

for inserting we will use push function.

Now of we add 3 in 1st stack and 4 in 2nd stack Value in top if ith index will denote top element of corresponding stack and the value of will get stored at arrĮx: let n = 4 and k=2 arr= Top be array of size 3(k=3) which will store top position of stack Let arr be array of size 9(n=9) which will store values of elements

We will initialize all elements of arr with -1 index with -1 in it is considered to be and empty indexĪnd initialize elements of top with starting elements of their stack Top of size k for storing top positions of stacks In this method we will create array of some size and divide that array into k parts for storing elements of k stacksįor implementing this first we will create two array arr of size n for storing values Let us get started with Implement K stacks in one array. The challenge is to efficiently store the elements to use all available space in the array and maintain the time complexity of stack operations. In this article, we have present two approaches to design K stacks in one array.